Comments on: The last positional parameter in bash http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/ Brian Pontarelli Wed, 08 Feb 2012 15:34:20 +0000 hourly 1 http://wordpress.org/?v=3.0.4 By: ol http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-132753 ol Sun, 22 May 2011 04:09:05 +0000 http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-132753 last="${!#}" last=”${!#}”

]]> By: marco http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-127025 marco Fri, 12 Nov 2010 02:40:58 +0000 http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-127025 function cu() { eval 'lasta=$'$#';'; echo $last; };cu a b c daaa function cu() { eval ‘lasta=$’$#’;'; echo $last; };cu a b c daaa

]]> By: nyighaj http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-79745 nyighaj Sun, 10 May 2009 12:12:14 +0000 http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-79745 last=$(echo $@ |cut -d\ -f $#) last=$(echo $@ |cut -d\ -f $#)

]]> By: nyighaj http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-79744 nyighaj Sun, 10 May 2009 12:11:52 +0000 http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-79744 $(echo $@ |cut -d\ -f $#) $(echo $@ |cut -d\ -f $#)

]]> By: Tomas Pospisek http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-35168 Tomas Pospisek Wed, 05 Nov 2008 22:13:23 +0000 http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-35168 Crap. It's the following that works better: eval “last=\${$#}” Crap. It’s the following that works better:

eval “last=\${$#}”

]]> By: Tomas Pospisek http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-35167 Tomas Pospisek Wed, 05 Nov 2008 22:12:29 +0000 http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-35167 The following works better: eval "last=\\${$#}" The following works better:

eval “last=\\${$#}”

]]> By: rocket http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-5606 rocket Wed, 05 Dec 2007 23:27:29 +0000 http://brian.pontarelli.com/2007/11/27/the-last-positional-parameter-in-bash/#comment-5606 To get the REST of the parameters: eval "rest=\"`for d in \`seq 1 \$[\$# - 1]\`; do echo -n \\\$\$d\ ; done`\"" To get the REST of the parameters:

eval “rest=\”`for d in \`seq 1 \$[\$# - 1]\`; do echo -n \\\$\$d\ ; done`\”"

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