The last positional parameter in bash

7 Responses to The last positional parameter in bash

1. rocket says:

   December 5, 2007 at 6:27 pm

   To get the REST of the parameters:

   eval “rest=\”`for d in \`seq 1 \$[\$# - 1]\`; do echo -n \\\$\$d\ ; done`\”"

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2. Tomas Pospisek says:

   November 5, 2008 at 5:12 pm

   The following works better:

   eval “last=\\${$#}”

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3. Tomas Pospisek says:

   November 5, 2008 at 5:13 pm

   Crap. It’s the following that works better:

   eval “last=\${$#}”

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4. nyighaj says:

   May 10, 2009 at 7:11 am

   $(echo $@ |cut -d\ -f $#)

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5. nyighaj says:

   May 10, 2009 at 7:12 am

   last=$(echo $@ |cut -d\ -f $#)

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6. marco says:

   November 11, 2010 at 9:40 pm

   function cu() { eval ‘lasta=$’$#’;'; echo $last; };cu a b c daaa

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   • ol says:

     May 21, 2011 at 11:09 pm

     last=”${!#}”

     Reply